0=(30*(x^2))+(53x)+5

Solution for 0=(30*(x^2))+(53x)+5 equation:

0=(30(x^2))+(53x)+5

We move all terms to the left:

0-((30(x^2))+(53x)+5)=0

determiningTheFunctionDomain
-(30x^2+53x+5)+0=0

We add all the numbers together, and all the variables

-(30x^2+53x+5)=0

We get rid of parentheses

-30x^2-53x-5=0

a = -30; b = -53; c = -5;
Δ = b2-4ac
Δ = -532-4·(-30)·(-5)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-47}{2*-30}=\frac{6}{-60}
=-1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+47}{2*-30}=\frac{100}{-60}
=-1+2/3
$